1. Reading image and the convert to binary image.
I = imread('aaa.png');
I =im2bw(double(I),0.5);
[y,x]=find(I);
[sy,sx]=size(I);
imshow(I);
2. Find all the require information for the transformatin. the 'totalpix' is the numbers of '1' in the image.
totalpix = length(x);
3. Preallocate memory for the Hough Matrix. Try to play around with the R, or the radius to see the different results.
HM = zeros(sy,sx,50);
R = 1:50;
R2 = R.^2;
sz = sy*sx;
4. Performing Hough Transform. Notice the accumulator is located in the inner for loop. This portion of codes will map the original image to the a-b domain.
for cnt = 1:totalpix
for cntR = 1:50
b = 1:sy;
a = (round(x(cnt) - sqrt(R2(cntR) - (y(cnt) - [1:sy]).^2)));
b = b(imag(a)==0 & real(a)>0);
a = a(imag(a)==0 & real(a)>0);
ind = sub2ind([sy,sx],b,a);
HM(sz*(cntR-1)+ind) = HM(sz*(cntR-1)+ind) + 1;
end
end
5. Find for the maximum value for each layer, or in other words, the layer with maximum value will indicate the correspond R for the circle.
for cnt = 1:50
H(cnt) = max(max(HM(:,:,cnt)));
end
plot(H,'*-');